{"id":18082,"date":"2024-03-17T01:04:34","date_gmt":"2024-03-17T01:04:34","guid":{"rendered":"https:\/\/soicau4032.minhngocxoso.com\/?p=18082"},"modified":"2024-03-17T01:04:34","modified_gmt":"2024-03-17T01:04:34","slug":"kinh-nghiem-soi-cau-lo-de-mb-an-chac","status":"publish","type":"post","link":"https:\/\/caulo100.com\/kinh-nghiem-soi-cau-lo-de-mb-an-chac\/","title":{"rendered":"kinh nghi\u1ec7m soi c\u1ea7u l\u00f4 \u0111\u1ec1 mb \u0103n ch\u1eafc"},"content":{"rendered":"\n
Ch\u00e0o c\u00e1c anh em, ch\u01a1i l\u00f4 \u0111\u1ec1 \u0111\u01b0\u1ee3c m\u1ed9t th\u1eddi gian t\u00f4i \u0111\u00e3 t\u00ecm hi\u1ec3u \u0111\u01b0\u1ee3c t\u1ea5t t\u1ea7n t\u1eadt v\u1ec1 c\u00e1c c\u00e1ch ch\u01a1i, m\u1eb9o ch\u01a1i, quy lu\u1eadt c\u1ee7a nh\u1eefng con s\u1ed1,\u2026 B\u00e0i vi\u1ebft n\u00e0y t\u00f4i s\u1ebd chia s\u1ebb t\u1edbi anh em kinh nghi\u1ec7m x\u01b0\u01a1ng m\u00e1u, nh\u1eefng c\u00f4ng th\u1ee9c v\u00e0 quy lu\u1eadt soi c\u1ea7u l\u00f4 \u0111\u1ec1 mb, \u0111\u1ea3m b\u1ea3o ch\u01a1i l\u00e0 tr\u00fang!<\/p>\n\n\n\n
S\u1ebd l\u00e0 quen \u0111\u1ed1i v\u1edbi ng\u01b0\u1eddi bi\u1ebft v\u00e0 l\u1ea1 v\u1edbi nh\u1eefng ng\u01b0\u1eddi m\u1edbi ti\u1ebfp c\u1eadn v\u1edbi lo\u1ea1i h\u00ecnh c\u00e1 c\u01b0\u1ee3c n\u00e0y n\u00f3i chung v\u00e0 soi c\u1ea7u n\u00f3i ri\u00eang.<\/p>\n\n\n\n
\u0110\u1ec3 hi\u1ec3u \u0111\u01b0\u1ee3c thu\u1eadt ng\u1eef n\u00e0y ta c\u1ea7n hi\u1ec3u v\u1ec1 \u201cc\u1ea7u\u201d. \u201cC\u1ea7u\u201d trong soi c\u1ea7u x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc xsmb l\u00e0 t\u1eadp h\u1ee3p c\u00e1c c\u1eb7p s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1 \u0111\u01b0\u1ee3c gh\u00e9p l\u1ea1i b\u1edfi c\u00e1c con s\u1ed1 t\u1eeb 0 \u0111\u1ebfn 9. C\u00e1c c\u1eb7p s\u1ed1 n\u00e0y \u0111\u01b0\u1ee3c gh\u00e9p theo m\u1ed9t quy lu\u1eadt ri\u00eang trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc h\u00e0ng ng\u00e0y.<\/p>\n\n\n\n
Soi c\u1ea7u l\u00f4 \u0111\u1ec1 mb c\u01a1 b\u1ea3n \u0111\u01b0\u1ee3c hi\u1ec3u l\u00e0 vi\u1ec7c d\u00f9ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc nh\u1eefng ng\u00e0y tr\u01b0\u1edbc theo c\u00f4ng th\u1ee9c v\u00e0 quy lu\u1eadt \u0111\u1ec3 t\u00ednh ra con l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c trong ng\u00e0y h\u00f4m nay. Bi\u1ebft \u0111\u01b0\u1ee3c c\u00f4ng th\u1ee9c v\u00e0 quy lu\u1eadt soi c\u1ea7u ch\u00ednh x\u00e1c<\/strong> n\u00e0y b\u1ea1n \u0111\u00e3 n\u1eafm ch\u1eafc \u0111\u01b0\u1ee3c 90% c\u01a1 h\u1ed9i thu ti\u1ec1n v\u1ec1 t\u00fai r\u1ed3i \u0111\u1ea5y!<\/p>\n\n\n\n – B\u01b0\u1edbc th\u1ee9 nh\u1ea5t, b\u1ea1n h\u00e3y ghi l\u1ea1i k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1 c\u1ee7a 2 ng\u00e0y g\u1ea7n nh\u1ea5t ra gi\u1ea5y theo m\u1ed9t h\u00e0ng ngang, m\u1ed7i ng\u00e0y vi\u1ebft tr\u00ean m\u1ed9t h\u00e0ng ri\u00eang bi\u1ec7t<\/p>\n\n\n\n A + B + C = 10 ho\u1eb7c 20<\/p>\n\n\n\n Trong \u0111\u00f3:<\/p>\n\n\n\n A l\u00e0 ch\u1eef s\u1ed1 \u0111\u1ea7u ti\u00ean trong k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1<\/p>\n\n\n\n B l\u00e0 ch\u1eef s\u1ed1 th\u1ee9 hai trong k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1<\/p>\n\n\n\n C l\u00e0 c\u1eb7p \u0111\u1ec1 b\u1ea1n mu\u1ed1n t\u00ecm trong ng\u00e0y h\u00f4m nay (m\u1ed9t \u1ea9n s\u1ed1 b\u1ea1n t\u1ef1 quy \u0111\u1ecbnh)<\/p>\n\n\n\n 10 ho\u1eb7c 20 l\u00e0 \u0111i\u1ec1u ki\u1ec7n k\u1ebft qu\u1ea3 (10 d\u00f9ng cho c\u1eb7p l\u00f4 \u0111\u1ec1 c\u00f3 t\u1ed5ng d\u01b0\u1edbi 10, c\u00f2n 20 d\u00f9ng cho c\u1eb7p l\u00f4 \u0111\u1ec1 c\u00f3 t\u1ed5ng d\u01b0\u1edbi 20)<\/p>\n\n\n\n \u0110\u1ec3 d\u1ec5 hi\u1ec3u t\u00f4i l\u1ea5y cho anh em m\u1ed9t v\u00ed d\u1ee5 c\u1ee5 th\u1ec3 \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c tr\u00ean:<\/p>\n\n\n\n H\u00f4m nay l\u00e0 ng\u00e0y 13 v\u00e0 anh em mu\u1ed1n soi c\u1ea7u \u0111\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3, anh em h\u00e3y t\u00ecm l\u1ea1i k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1 2 ng\u00e0y 11 v\u00e0 12 v\u00e0 l\u1ea5y gi\u1ea5y b\u00fat ghi l\u1ea1i theo 2 h\u00e0ng ngang<\/p>\n\n\n\n N\u1ebfu k\u1ebft qu\u1ea3 ng\u00e0y 11 l\u00e0 56, ta c\u00f3 c\u00f4ng th\u1ee9c: 5+6+C=20 suy ra C=20-5-6=9<\/p>\n\n\n\n N\u1ebfu k\u1ebft qu\u1ea3 ng\u00e0y 12 l\u00e0 24, ta c\u00f3 c\u00f4ng th\u1ee9c: 2+4+C=10 suy ra C=10-2-4=4<\/p>\n\n\n\n Sau \u0111\u00f3 b\u1ea1n gh\u00e9p 2 k\u1ebft qu\u1ea3 l\u1ea1i v\u1edbi nhau ta \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1 c\u1ee7a ng\u00e0y h\u00f4m nay (ng\u00e0y 13) l\u00e0 94.<\/p>\n\n\n\n \u0110\u00f3 l\u00e0 c\u00e1c b\u01b0\u1edbc \u0111\u1ec3 b\u1ea1n t\u00ednh l\u00f4 \u0111\u1ec1 c\u1ee7a ng\u00e0y b\u1ea1n mu\u1ed1n \u0111\u00e1nh hay g\u1ecdi kh\u00e1c l\u00e0 soi c\u1ea7u l\u00f4 \u0111\u1ec1 mb. Anh em c\u1ea7n ph\u1ea3i theo quy lu\u1eadt m\u1edbi c\u00f3 th\u1ec3 \u0111\u1ea3m b\u1ea3o tr\u00fang n\u1ebfu kh\u00f4ng n\u00f3i \u0111\u1ebfn y\u1ebfu t\u1ed1 may m\u1eafn!<\/p>\n\n\n\nC\u00e1ch soi l\u00f4 \u0111\u1ec1 chu\u1ea9n<\/strong> \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/h5>\n\n\n\n
– B\u01b0\u1edbc th\u1ee9 hai h\u00e3y ti\u1ebfn h\u00e0nh c\u1ed9ng c\u00e1c con s\u1ed1 \u0111\u00f3 l\u1ea1i theo c\u00f4ng th\u1ee9c:<\/h5>\n\n\n\n